Uniform Circular Motion Calculator
Solve any uniform circular motion problem instantly using the complete set of centripetal motion equations — period, frequency, angular velocity, centripetal acceleration, centripetal force, and normal force in vertical circles. Built for physics students and AP Physics 1 courses.
This uniform circular motion calculator solves the complete set of centripetal motion equations for period, frequency, angular velocity, linear speed, centripetal acceleration, centripetal force, and normal force — all from any two known variables. Whether you're checking homework, prepping for an AP Physics exam, or working an engineering problem, enter your known values below and every related quantity of your uniform circular motion problem is calculated instantly with full step-by-step working.
Watch the dot travel at constant speed around the path. Notice the blue velocity arrow always points tangent to the circle, while the coral centripetal acceleration/force arrow always points straight to the center — this is exactly why, in uniform circular motion, speed is constant but velocity is not.
Choose how you want to calculate centripetal force — from speed, from angular velocity, or directly from centripetal acceleration.
Formula: Fc = mv²/r
Formula: Fc = mω²r
Formula: Fc = m·aₙ
Centripetal Force (Fc)
What Provides Centripetal Force? — Real-World Situations
Centripetal force is never a separate, distinct force on a free-body diagram — it's simply the label for whichever real force (or combination of forces) is pointed toward the center of the circular path.
⚡ Quick RPM Converter — the most common circular motion conversion. Enter RPM and instantly get frequency, period, and angular velocity.
Normal force always points toward the center — this diagram shows the object's position and the inward direction of N.
Fill in v + r to find ω, or ω + r to find v. Formulas: ω = v/r | v = ωr
The period T of uniform circular motion is the time for one complete revolution. T = 2πr/v = 2π/ω = 1/f. Period stays constant throughout uniform circular motion since speed and radius don't change.
Frequency f is the number of complete revolutions per second, measured in Hz. f = 1/T = ω/(2π). RPM (revolutions per minute) converts to Hz via f = RPM/60.
Angular velocity ω measures how fast the angle sweeps out, in rad/s. ω = 2πf = 2π/T = v/r. It stays constant in uniform circular motion.
Linear speed v is the constant tangential speed of the object along the circular path. v = 2πr/T = ωr. In uniform circular motion, this magnitude never changes — only its direction (always tangent) does.
Centripetal acceleration aₙ points toward the center of the circle at every instant. aₙ = v²/r = ω²r = 4π²r/T². This centripetal acceleration exists purely because the direction of velocity is changing.
Centripetal force is the net inward force required to keep an object moving in a circle. Fc = mv²/r = mω²r = m·aₙ. It is not a new type of force — it's provided by tension, gravity, friction, or normal force.
At the top of a vertical circle, both gravity and the normal force point toward the center (downward), so N = mv²/r − mg. The minimum speed for contact is v_min = √(gr), where N = 0.
At the bottom of a vertical circle, gravity points away from the center while normal force points toward it, so N = mv²/r + mg — always greater than the object's weight.
| Quantity | Symbol | Equivalent Formulas | Units |
|---|---|---|---|
| Period | T | T = 2πr/v = 2π/ω = 1/f | s |
| Frequency | f | f = 1/T = ω/(2π) = RPM/60 | Hz |
| Angular Velocity | ω | ω = 2πf = 2π/T = v/r | rad/s |
| Linear Speed | v | v = 2πr/T = ωr | m/s |
| Centripetal Acceleration | aₙ | aₙ = v²/r = ω²r = 4π²r/T² | m/s² |
| Centripetal Force | Fc | Fc = mv²/r = mω²r = m·aₙ | N |
| Normal Force (top) | N | N = mv²/r − mg | N |
| Normal Force (bottom) | N | N = mv²/r + mg | N |
What Is Uniform Circular Motion?
Uniform circular motion is motion at a constant speed along a circular path. The word "uniform" refers only to the speed — it does not mean the object experiences no acceleration. This is the single most tested conceptual point in AP Physics 1 circular motion problems.
Here's the key idea: velocity is a vector with both magnitude (speed) and direction. In uniform circular motion, the magnitude of velocity never changes, but the direction is constantly rotating to stay tangent to the circle. In other words, speed is constant but velocity is not. Because velocity is continuously changing direction, the object must have an acceleration — this is the centripetal acceleration, and it always points toward the center of the circle.
What is constant in uniform circular motion? Speed (magnitude of velocity), radius, angular velocity ω, period T, and the magnitude of centripetal acceleration and centripetal force. What changes: the direction of velocity, the direction of acceleration, and the direction of centripetal force — all three rotate continuously around the circle.
When is an object moving in uniform circular motion? An object is in uniform circular motion whenever it travels at constant speed along a circular path of fixed radius — a satellite in a circular orbit, a car rounding a curve at steady speed, or a point on a spinning wheel are all classic uniform circular motion examples.
Uniform Circular Motion Formulas — Complete List
Below are all the UCM formulas (also called UCM equations) needed to solve any uniform circular motion problem. Because every variable is mathematically linked, changing one quantity changes all the others through these circular motion equations.
| Name | Formula | Solved From |
|---|---|---|
| Period | T = 2πr/v = 2π/ω | radius & speed, or angular velocity |
| Frequency | f = 1/T | period |
| Angular velocity | ω = 2πf = 2π/T = v/r | frequency, period, or v & r |
| Linear speed | v = 2πr/T = ωr | radius & period, or ω & r |
| Centripetal acceleration | aₙ = v²/r = ω²r = 4π²r/T² | v & r, or ω & r |
| Centripetal force | Fc = mv²/r = mω²r = m·aₙ | mass + any centripetal acceleration path |
Notice how every uniform circular motion formula connects back to just two independent quantities — typically radius and speed, or radius and period. Once you know any two of {r, v, T, f, ω}, every other centripetal motion equation can be solved.
Centripetal Acceleration and Force Explained
Centripetal acceleration (center-seeking acceleration) always points toward the center of the circular path and is always perpendicular to the velocity vector. It has magnitude aₙ = v²/r = ω²r and exists purely because the direction of velocity is changing — not because speed is changing.
Centripetal force is the single biggest misconception in circular motion physics. Centripetal force is not a new, separate force that appears on a free-body diagram alongside gravity, tension, friction, and normal force. Instead, "centripetal force" is simply the name given to whichever real force (or net combination of real forces) happens to point toward the center and causes the circular path. Writing "Fc" as an extra arrow on a free-body diagram is a common error that AP Physics 1 graders specifically deduct points for.
Period of Circular Motion — Formula and Examples
The period of circular motion is the time required to complete exactly one full revolution. The core formula is T = 2πr/v, with the equivalent forms T = 2π/ω and T = 1/f. The RPM connection is direct: T = 60/RPM seconds per revolution.
Worked Example 1 — Car on a Circular Track
- Given: radius r = 50 m, speed v = 20 m/s
- Apply period formula: T = 2πr/v = 2π(50)/20
- T = 100π/20 = 5π ≈ 15.71 s
- Centripetal acceleration: aₙ = v²/r = 400/50 = 8 m/s²
Worked Example 2 — Satellite Orbit Period (AP Physics Favorite)
- Given: Earth orbiting Sun, r = 1.496×10¹¹ m, T = 365.25 days = 31,557,600 s
- Linear speed: v = 2πr/T = 2π(1.496×10¹¹)/31,557,600 ≈ 29,785 m/s
- Centripetal acceleration: aₙ = v²/r ≈ 0.00593 m/s²
- Angular velocity: ω = v/r ≈ 1.99×10⁻⁷ rad/s
Normal Force in Circular Motion — Vertical Circles
For an object moving in a vertical circle — a roller coaster loop or a ball on a string swung overhead — the normal force N is not constant. It changes depending on position because gravity sometimes helps provide centripetal force and sometimes opposes it.
At the top of the loop, both gravity and the normal force point toward the center (downward): N = mv²/r − mg. There's a critical minimum speed where N drops to exactly zero — gravity alone supplies all the centripetal force: v_min = √(gr). This is often mislabeled "weightlessness," but gravity hasn't vanished — the track simply stops needing to push at all.
At the bottom of the loop, gravity points away from the center while the normal force points toward it: N = mv²/r + mg — always larger than the object's actual weight, which is why riders feel heaviest at the bottom of a loop.
Worked Example 3 — Roller Coaster Loop
- Given: m = 500 kg, r = 15 m, v = 18 m/s
- Centripetal force: Fc = mv²/r = 500(18)²/15 = 10,800 N
- Normal force at top: N = Fc − mg = 10,800 − 500(9.80665) ≈ 5,897 N (positive → maintains contact ✓)
- Normal force at bottom: N = Fc + mg = 10,800 + 500(9.80665) ≈ 15,703 N
Worked Example 4 — Minimum Speed Check
- Given: r = 15 m. Minimum speed at top: v_min = √(gr) = √(9.80665 × 15) ≈ 12.13 m/s
- If actual speed is only v = 8 m/s (below v_min), normal force becomes negative
- N = 500(8)²/15 − 500(9.80665) = 2,133.3 − 4,903.3 ≈ −2,770 N
- Since N cannot be negative, this means the object leaves the circular path before reaching the top
Uniform Circular Motion Examples — Step-by-Step Problems
1. Centripetal Acceleration of a Car Rounding a Curve
A car rounds a curve of radius 40 m at 15 m/s. Find its centripetal acceleration.
- aₙ = v²/r = 15²/40 = 225/40 = 5.625 m/s²
2. Minimum Speed to Complete a Vertical Loop
Find the minimum speed for a 2 kg ball on a string of radius 0.8 m to complete a vertical loop.
- v_min = √(gr) = √(9.80665 × 0.8) ≈ 2.80 m/s
3. Earth's Orbital Period and Speed Given Radius
Given r = 1.496×10¹¹ m and T = 1 year, find v and centripetal acceleration (see Worked Example 2 above): v ≈ 29,785 m/s, aₙ ≈ 0.00593 m/s².
4. Washing Machine Drum: RPM to Centripetal Acceleration
A washing machine drum of radius 0.25 m spins at 1,200 RPM. Find centripetal acceleration.
- f = 1200/60 = 20 Hz → ω = 2π(20) = 125.66 rad/s
- v = ωr = 125.66 × 0.25 = 31.4 m/s
- aₙ = v²/r = 31.4²/0.25 ≈ 3,948 m/s²
5. Satellite Orbit: Given Period, Find Radius (Kepler's 3rd Law Connection)
For satellites, T² is proportional to r³ (Kepler's Third Law) when gravity alone provides the centripetal force: setting Fc = mv²/r equal to gravitational force GMm/r² leads directly to T² ∝ r³ — a brief but important bridge between uniform circular motion and orbital mechanics.
6. Ball on String: Maximum Speed Before String Breaks
A string can withstand 50 N of tension. A 0.5 kg ball swings on a 1.2 m string. Find max speed.
- Fc = Tmax = mv²/r → 50 = 0.5v²/1.2
- v² = 50 × 1.2/0.5 = 120 → v = 10.95 m/s
7. Banked Curve Problem: Ideal Banking Angle
For a frictionless banked curve, the ideal angle satisfies tan θ = v²/(rg). For v = 25 m/s, r = 200 m: tan θ = 625/(200×9.80665) = 0.3189 → θ ≈ 17.7°.
8. Car on Flat Track: Maximum Speed Before Skidding
Given coefficient of friction μ = 0.7 and radius r = 60 m, friction alone provides centripetal force: μmg = mv²/r → v = √(μgr) = √(0.7 × 9.80665 × 60) ≈ 20.3 m/s.
AP Physics 1 Circular Motion — Key Concepts and Common Mistakes
These five concepts are the most frequently tested uniform circular motion points on the AP Physics 1 exam:
- Centripetal force is not a separate, distinct force — it's the name for whatever net inward force (tension, gravity, friction, normal force) causes the circular motion.
- Speed is constant, but velocity is not — "uniform" only describes speed, and the object still has a nonzero centripetal acceleration.
- Centripetal acceleration direction is always radially inward, toward the center — never tangent, never outward.
- At the top of a vertical loop, minimum speed gives N = 0, not "no gravity" — gravity is doing 100% of the centripetal force job at that instant.
- For satellites and orbits, period and radius are linked by T² ∝ r³ (Kepler's Third Law), extending uniform circular motion into orbital mechanics.
Five of the most common mistakes students make in uniform circular motion problems:
- Drawing centripetal force as a separate, extra arrow on a free-body diagram instead of correctly labeling the real force that provides it.
- Confusing centripetal (real, inward) force with centrifugal (fictitious, outward) force felt only in a rotating reference frame.
- Plugging in the diameter instead of the radius into centripetal acceleration or centripetal force formulas — always double the error.
- Forgetting to convert RPM to rad/s (multiply by 2π/60) before using it in centripetal motion equations.
- Sign errors on normal force at the top vs. bottom of a vertical loop — remember gravity subtracts at the top and adds at the bottom.
📌 Remember: In every uniform circular motion problem, centripetal force is a role, not a new force. Ask "what real force is pointing toward the center here?" before writing any free-body diagram.
Frequently Asked Questions
What is uniform circular motion?
What is constant in uniform circular motion?
What is centripetal acceleration?
What provides centripetal force?
What is the formula for period in circular motion?
How do you find centripetal force?
What is the difference between centripetal and centrifugal force?
What happens at minimum speed at the top of a loop?
This uniform circular motion calculator provides estimates for educational purposes using standard idealized physics formulas (g = 9.80665 m/s²). Real-world circular motion problems may involve air resistance, friction losses, or non-ideal conditions not modeled here.
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