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Truncated Cone Calculator — Frustum Volume & Surface Area

Truncated Cone Calculator — Frustum Volume & Surface Area
Geometry Calculator

Truncated Cone Calculator (Frustum)

Calculate the volume, surface area, lateral area, and slant height of any truncated cone (frustum) — the solid formed by cutting a cone parallel to its base. Complete step-by-step working with cone-subtraction verification for every calculation.

Truncated Cone Calculator — Frustum
V = (πh/3)(R²+Rr+r²)  |  l = √(h²+(R−r)²)  |  LA = π(R+r)l  |  SA = π(R²+r²+(R+r)l)
R r h l Large base: R Small base: r l = √(h²+(R−r)²)

Enter R, r, h — plus optionally l or V for verification/alternative input:

R=6,r=3,h=4 (classic)
Bucket R=15,r=10,h=20
Shallow R=10,r=9,h=2
R=5,r=2,h=8
R=8,r=4,h=6
R=10,r=5,h=12
R=12,r=6,h=8
Error
Step-by-Step Working

Slide to see how the truncated cone transitions between a full cone (r=0) and a cylinder (r=R). Base: R=6, h=8 cm.

r/R ratio: 0.50 Truncated Cone
r=0 (Cone)r=R/2 (Frustum)r=R (Cylinder)
Small radius r
3.0 cm
Volume V
Slant height l
R = 6 cm r = 3 cm h=8
Special Case Analysis

A truncated cone (frustum) = large full cone minus small full cone. Enter R, r, h to see the subtraction method.

Error
Cone Subtraction Working

What Is a Truncated Cone (Frustum)?

A truncated cone — also called a frustum — is the solid formed when a cone is cut by a plane parallel to its base, removing the top portion. The result is a three-dimensional shape with two circular bases of different sizes: a large base of radius R at the bottom and a small base of radius r at the top, connected by a slanted lateral surface.

The word frustum comes from Latin meaning "morsel" or "piece cut off." Truncated cones appear everywhere in everyday life: buckets, drinking cups, traffic cones, paper cups, wine glasses, lampshades, cooling towers, and even the frustum shape of many mountains. This truncated cone calculator handles all frustum calculations including volume of a truncated cone, surface area of a truncated cone, and slant height.

Key distinction: When r = 0, the truncated cone becomes a full cone (volume = (πh/3)R²). When r = R, it becomes a cylinder (volume = πR²h). Any value 0 < r < R gives a true frustum — a truncated cone.

Truncated Cone Formula — Volume, Surface Area & Slant Height

All truncated cone formulas depend on three variables: R (large base radius), r (small base radius), and h (perpendicular height). The slant height l is derived from these using the Pythagorean theorem.

V = (πh/3)(R² + Rr + r²) Truncated cone volume formula — the middle term Rr is most commonly forgotten!
PropertySymbolFormulaNotes
VolumeV(πh/3)(R²+Rr+r²)Three-term expression — never forget Rr
Slant heightl√(h²+(R−r)²)(R−r) is horizontal reach
Lateral areaLAπ(R+r)lCurved surface only
Total surface areaSAπ(R²+r²+(R+r)l)Lateral + both circles
Bottom areaA_botπR²Large base circle
Top areaA_topπr²Small base circle

Why the truncated cone volume formula has three terms

The expression (R² + Rr + r²) in the volume formula V = (πh/3)(R² + Rr + r²) comes from the algebraic expansion of V_large_cone − V_small_cone. By similar triangles, the full large cone has height H = hR/(R−r) and the removed small cone has height (H−h) = hr/(R−r). Subtracting gives exactly (πh/3)(R² + Rr + r²). The middle term Rr is a cross-term from the expansion — the most commonly forgotten term in the truncated cone formula.

How to Calculate Truncated Cone Volume — Step-by-Step

Follow four steps to find the volume of a truncated cone reliably:

  1. Identify R (large base radius), r (small base radius), and h (perpendicular height)
  2. Compute the three-term expression: R² + Rr + r²
  3. Multiply by πh/3
  4. Verify: if r=0, should give (πh/3)R²; if r=R, should give πR²h

Example 1 — R=6, r=3, h=4 cm (truncated cone)

  1. l = √(h²+(R−r)²) = √(16+9) = √25 = 5 cm (3-4-5 triple!)
  2. V = (π×4/3)(6²+6×3+3²) = (4π/3)(36+18+9) = (4π/3)(63) = 84π ≈ 263.894 cm³
  3. LA = π(6+3)×5 = 45π ≈ 141.372 cm²
  4. SA = π(36+9+45) = 90π ≈ 282.743 cm²

Example 2 — Bucket: R=15, r=10, h=20 cm

  1. l = √(400+25) = √425 ≈ 20.616 cm
  2. V = (π×20/3)(225+150+100) = (20π/3)(475) = 9500π/3 ≈ 9948.4 cm³ ≈ 9.95 L
  3. LA = π(15+10)×20.616 = 515.4π ≈ 1619.0 cm²

Example 3 — Very shallow frustum: R=10, r=9, h=2 cm

  1. l = √(4+1) = √5 ≈ 2.236 cm
  2. V = (π×2/3)(100+90+81) = (2π/3)(271) = 542π/3 ≈ 567.6 cm³

Surface Area of a Truncated Cone

The surface area of a truncated cone (total SA) consists of three parts: the large base circle (πR²), the small base circle (πr²), and the lateral curved surface (π(R+r)l). Combined: SA = π(R² + r² + (R+r)l).

SA = πR² + πr² + π(R+r)l Large circle + small circle + lateral surface = total surface area of truncated cone

The lateral area formula LA = π(R+r)l can be understood geometrically: when the lateral surface of a truncated cone is "unrolled," it forms a portion of an annulus (ring-shaped sector). The factor π(R+r) is related to the average circumference of the two bases — it represents the arithmetic mean of the two base perimeters multiplied by the slant height l.

Surface area breakdown: R=6, r=3, l=5 cm

  • Bottom circle: πR² = 36π ≈ 113.10 cm²
  • Top circle: πr² = 9π ≈ 28.27 cm²
  • Lateral surface: π(R+r)l = π×9×5 = 45π ≈ 141.37 cm²
  • Total SA = (36+9+45)π = 90π ≈ 282.74 cm²

Truncated Cone vs Full Cone — Special Cases

The truncated cone formula is a generalization that reduces to the full cone and cylinder formulas at the extremes:

CaseConditionVolume formula reduces toVerification
Full coner = 0(πh/3)(R²+0+0) = (1/3)πR²h✓ Standard cone formula
Cylinderr = R(πh/3)(R²+R²+R²) = (πh/3)(3R²) = πR²h✓ Standard cylinder formula
Frustum0 < r < R(πh/3)(R²+Rr+r²)Interpolates between cone and cylinder

Quick verification trick: Always check your truncated cone answer by testing the special cases. Set r=0 in your formula — does it give the cone formula? Set r=R — does it give the cylinder formula? If both checks pass, the formula is correct.

Real-World Examples of Truncated Cones

Plastic Bucket: R=15cm, r=12cm, h=25cm

  1. V = (π×25/3)(225+180+144) = (25π/3)(549) = 4575π ≈ 14,373 cm³ = 14.37 L
  2. LA = π(15+12)×√(625+9) = 27π×√634 ≈ 2136 cm²

Paper Drinking Cup: R=4cm, r=3cm, h=9cm

  1. l = √(81+1) = √82 ≈ 9.055 cm
  2. V = (π×9/3)(16+12+9) = 3π×37 = 111π ≈ 348.7 cm³ ≈ 349 mL

Traffic Cone: R=15cm, r=3cm, h=45cm

  1. l = √(2025+144) = √2169 ≈ 46.57 cm
  2. V = (π×45/3)(225+45+9) = 15π×279 = 4185π ≈ 13,148 cm³

Common Mistakes With Truncated Cone Calculations

Mistake 1 — Forgetting the Rr middle term

  • ❌ Wrong: V = (πh/3)(R²+r²) — missing the Rr term
  • ✅ Correct: V = (πh/3)(R²+Rr+r²) — all three terms are required
  • For R=6,r=3,h=4: Wrong gives (4π/3)(45)=60π; Correct gives (4π/3)(63)=84π — 40% error!

Mistake 2 — Wrong slant height: using h instead of (R−r)

  • ❌ Wrong: l = √(h²+R²) — treats R as the horizontal reach
  • ✅ Correct: l = √(h²+(R−r)²) — (R−r) is the horizontal difference between radii

Mistake 3 — Swapping R and r (forgetting R ≥ r)

  • Convention: R is always the LARGER base radius (bottom). r is the smaller (top). The formula is symmetric in some ways but keep R≥r for correct slant height: (R−r) must be ≥ 0.

Mistake 4 — Forgetting both base circles in total SA

  • ❌ Wrong (lateral only): LA = π(R+r)l — gives curved surface only
  • ✅ Correct (total): SA = πR² + πr² + π(R+r)l — must add both circle bases

Mistake 5 — Using cone formula V=(1/3)πR²h for a frustum

  • The cone formula only applies when r=0. For any truncated cone with r>0, you must use V=(πh/3)(R²+Rr+r²). Using the cone formula underestimates the true frustum volume.

Frequently Asked Questions

What is a truncated cone?
A truncated cone (frustum) is a cone with its top sliced off by a plane parallel to the base. It has two circular bases: large radius R (bottom) and small radius r (top), and a slanted lateral surface connecting them. Real examples include buckets, cups, lampshades, and cooling towers. When r=0, it becomes a full cone; when r=R, it becomes a cylinder.
What is the formula for the volume of a truncated cone?
The truncated cone volume formula is V = (πh/3)(R² + Rr + r²), where R is the large base radius, r is the small base radius, and h is the perpendicular height. The middle term Rr is critical and often forgotten. Example: R=6, r=3, h=4 → V = (4π/3)(36+18+9) = (4π/3)(63) = 84π ≈ 263.894 cm³.
What is a frustum?
A frustum is the portion of a cone remaining after removing the top with a cut parallel to the base. A conical frustum = truncated cone. It has two circular bases of different radii (R and r) and a slanted lateral surface of slant height l = √(h²+(R−r)²). The frustum volume = V_large_cone − V_small_cone.
How do you find the slant height of a frustum?
The slant height of a frustum (truncated cone) is l = √(h² + (R−r)²), where h is the perpendicular height and (R−r) is the horizontal reach between the two bases. Example: R=6, r=3, h=4 → l = √(16+9) = √25 = 5 cm. This is the Pythagorean theorem on the right triangle formed by h, (R−r), and l.
What is the surface area of a truncated cone?
Total surface area = πR² (bottom) + πr² (top) + π(R+r)l (lateral). Combined: SA = π(R² + r² + (R+r)l). The lateral area LA = π(R+r)l covers only the curved surface. For R=6, r=3, l=5: SA = π(36+9+45) = 90π ≈ 282.74 cm².
What happens to a frustum when r equals zero?
When r=0: V = (πh/3)(R²+0+0) = (1/3)πR²h — the standard cone formula ✓. When r=R: V = (πh/3)(3R²) = πR²h — the cylinder formula ✓. These are the two limits and serve as verification checks for any truncated cone calculation.

Related Calculators

Frustum Formulas
V=(πh/3)(R²+Rr+r²)Volume — 3 terms, don't forget Rr
l=√(h²+(R−r)²)Slant height — Pythagoras
LA=π(R+r)lLateral curved surface
SA=π(R²+r²+(R+r)l)Total surface area
r=0 → V=(πh/3)R²Full cone limit
r=R → V=πR²hCylinder limit
Quick Examples
R=6,r=3,h=4 → 84π
Bucket R=15,r=10,h=20
Shallow R=10,r=9,h=2
R=8,r=4,h=6
Cone: R=5,r=0,h=8
Cylinder: R=r=6,h=5

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