Simplify Radicals Calculator
This simplify radicals calculator reduces any radical expression to its simplest radical form, adds and subtracts like radicals, multiplies radicals using the product rule, rationalizes the denominator, and solves radical equations — showing every step from prime factorization to the final simplified form.
Simplest Radical Form
Simplified Radical Expression
⚠️ Domain Assumption: All variables represent non-negative numbers (required for real-valued square roots).
Enter radical terms to add or subtract. Each row: coefficient × √radicand.
Combined Result
Rationalize: c / (a ± √b)
Result
Solve equations of the form √(ax + b) = c
Solution
What Is Simplest Radical Form? — Definition and Rules
A radical expression is in its simplest radical form when it satisfies all three of the following conditions. These are mathematical conventions that create a standardized form making it easy to compare, add, and work with radical expressions.
Condition 1: No Perfect Square Factors Under the Radical
No perfect square factor (other than 1) may remain under the radical sign. Perfect squares are 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144... When you see one of these as a factor of the radicand, you can pull its square root outside.
Example violation: √72 is NOT in simplest radical form — 72 = 36 × 2 and 36 is a perfect square. The simplest radical form is 6√2, because we pull √36 = 6 outside the radical.
Condition 2: No Fractions Under the Radical
No fraction may appear inside the radical sign. If you have √(3/4), rewrite it as √3/√4 = √3/2. This uses the quotient rule for radicals in reverse to eliminate the fraction inside.
Example violation: √(1/2) is NOT in simplest radical form. Correct form: √2/2 (rationalize the denominator).
Condition 3: No Radicals in the Denominator (Rationalize the Denominator)
No radical may appear in the denominator of a fraction. If you have 1/√2, you must rationalize the denominator by multiplying by √2/√2 to get √2/2. When the denominator is a binomial like (3 + √5), multiply by the conjugate (3 − √5).
Example violation: 5/√3 is NOT in simplest radical form. Correct form: 5√3/3 (multiply numerator and denominator by √3).
How to Simplify Radicals — Step-by-Step Method
There are two reliable methods to simplify radicals: the largest perfect square method (faster) and the prime factorization method (more systematic for large numbers). Both always give the same result.
Method 1: Largest Perfect Square Factor (Fastest)
- List the factor pairs of the radicand
- Identify all perfect square factors: 4, 9, 16, 25, 36, 49, 64, 81, 100…
- Select the largest perfect square factor
- Write the radicand as (largest perfect square) × (remaining)
- Apply the product rule: √(a×b) = √a × √b
- Simplify the square root of the perfect square
Method 2: Prime Factorization (Systematic)
- Find the complete prime factorization of the radicand
- Group prime factors into pairs
- Each pair contributes one factor outside the radical
- Unpaired factors remain inside the radical
Example: Simplify √48 — Both Methods
Method 1 (Largest Perfect Square):
- Perfect square factors of 48: 4, 16. Largest = 16
- 48 = 16 × 3
- √48 = √(16 × 3) = √16 × √3 = 4√3
Method 2 (Prime Factorization):
- 48 = 2 × 24 = 2 × 2 × 12 = 2 × 2 × 2 × 6 = 2⁴ × 3
- √48 = √(2⁴ × 3) = √(2² × 2² × 3)
- Each pair of 2s contributes one 2 outside: 2 × 2 × √3 = 4√3
- Result: 4√3 — same answer ✓
Example: Simplify √180
Method 1: 180 = 36 × 5 → √180 = 6√5
Method 2: 180 = 2² × 3² × 5 → √180 = 2 × 3 × √5 = 6√5 ✓
Example: Simplify √200
Method 1: 200 = 100 × 2 → √200 = 10√2
Method 2: 200 = 2³ × 5² → √200 = 2 × 5 × √2 = 10√2 ✓
Key insight: If you accidentally use a smaller perfect square (e.g., pulling out 4 from 72 to get 2√18), the answer is NOT fully simplified. Always find the LARGEST perfect square factor. Check if what remains under the radical still has a perfect square factor.
Simplifying Radical Expressions with Variables
For variables under a radical, the rule is: bring out the largest power that results in a whole number after dividing by the root index. For simplify radicals with a square root (index 2):
| Under Radical | Simplification | Reasoning |
|---|---|---|
| √(x²) | |x| (or x if x≥0) | x² is a perfect square |
| √(x⁴) | x² | x⁴ = (x²)², even power |
| √(x⁵) | x²√x | x⁵ = x⁴·x, bring out x² |
| √(x³) | x√x | x³ = x²·x, bring out x |
| √(x³y⁴) | xy²√x | x³=x²·x; y⁴=(y²)² |
| √(x⁶y²) | x³y | Both perfect squares — no radical needed |
Full Example: Simplify √(72x³y⁵)
- Separate: √72 × √(x³) × √(y⁵)
- Simplify √72: 72 = 36×2, so √72 = 6√2
- Simplify √(x³): x³ = x²·x, so √(x³) = x√x
- Simplify √(y⁵): y⁵ = y⁴·y, so √(y⁵) = y²√y
- Outside parts: 6 × x × y² = 6xy²
- Inside parts: √2 × √x × √y = √(2xy)
- Result: 6xy²√(2xy) (assuming x≥0, y≥0)
Domain Warning: √(x²) = |x|, NOT x, when x could be negative. We write √(x²) = x only when we know x ≥ 0. This is the most commonly missed domain restriction when simplifying radicals with variables.
Adding and Subtracting Radical Expressions
Only like radicals — radicals with the same radicand AND the same index — can be combined by addition or subtraction. Like radicals behave just like like terms: a√n + b√n = (a+b)√n.
Critical rule: √(a+b) ≠ √a + √b — this is the single most common mistake with radicals. You CANNOT distribute the radical over addition. √9 + √16 = 3 + 4 = 7, but √(9+16) = √25 = 5 ≠ 7.
Critical first step: Always simplify radicals before deciding if they are like radicals. Many radicals that look unlike become like after simplification.
Example 1 (Simple): 3√5 + 2√5
- Both terms already simplified. Same radicand (5) → like radicals ✓
- (3+2)√5 = 5√5
Example 2 (Simplify First): √12 + √27
- Simplify each: √12 = 2√3, √27 = 3√3
- Now both have radicand 3 → like radicals ✓
- 2√3 + 3√3 = 5√3
Example 3 (Unlike Radicals): √8 + √18 + √5
- Simplify each: √8 = 2√2, √18 = 3√2, √5 = √5
- Group by radicand: (2√2 + 3√2) + √5
- Combine like radicals: 5√2 + √5
- Result: 5√2 + √5 — cannot simplify further (different radicands)
Multiplying Radicals — The Product Rule
The product rule for radicals: √a × √b = √(ab), provided both a and b are non-negative. This product rule √a × √b = √(ab) works in both directions — use it to multiply radicals or to split a radical for simplification. The product rule √a × √b = √(ab) is the foundation of all radical multiplication.
Example: 3√8 × 5√6
- Multiply coefficients: 3 × 5 = 15
- Apply product rule: √8 × √6 = √48 (product rule √a × √b = √(ab))
- Combined: 15√48
- Simplify √48 = 4√3
- Result: 15 × 4√3 = 60√3
Example: FOIL — (2 + √3)(5 − √3)
- First: 2×5 = 10
- Outer: 2×(−√3) = −2√3
- Inner: √3×5 = 5√3
- Last: √3×(−√3) = −(√3)² = −3
- Combine: 10 − 2√3 + 5√3 − 3 = 7 + 3√3
- Result: 7 + 3√3
Important: The product rule for radicals only works when indices are the same. You cannot multiply √a × ∛b directly using √a × √b = √(ab) — they have different indices (2 and 3). Convert to rational exponents first: a^(1/2) × b^(1/3).
Rationalizing the Denominator — Simple and Conjugate Methods
The convention of not leaving radicals in the denominator is called rationalizing the denominator. It creates a standard form and simplifies further arithmetic.
Simple Case: a/√b
Multiply both numerator and denominator by √b. Since √b/√b = 1, the value is unchanged. Result: a√b/b.
Example: Rationalize 5/√3
- Multiply by √3/√3: (5/√3) × (√3/√3)
- Numerator: 5√3
- Denominator: √3 × √3 = 3
- Result: 5√3/3
Conjugate Case: c/(a ± √b)
When the denominator is a binomial containing a radical, multiply by the conjugate. The conjugate of (a + √b) is (a − √b). The product uses the difference of squares: (a + √b)(a − √b) = a² − b, which eliminates the radical from the denominator.
Example: Rationalize 4/(3 + √5)
- Conjugate of (3 + √5) is (3 − √5)
- Multiply: 4/(3+√5) × (3−√5)/(3−√5)
- Numerator: 4(3−√5) = 12 − 4√5
- Denominator: (3+√5)(3−√5) = 3² − (√5)² = 9 − 5 = 4
- Result: (12 − 4√5)/4
- Simplify: divide both terms by 4 → 3 − √5
Example: Rationalize 3/(2 − √7)
- Conjugate of (2 − √7) is (2 + √7)
- Multiply: 3/(2−√7) × (2+√7)/(2+√7)
- Numerator: 3(2+√7) = 6 + 3√7
- Denominator: 2² − (√7)² = 4 − 7 = −3
- Result: (6 + 3√7)/(−3) = −2 − √7
Solving Radical Equations — Isolate and Square
A radical equation contains a variable under a radical sign. The strategy: isolate the radical, then square both sides. But squaring both sides can introduce extraneous solutions — the CHECK step is mandatory, not optional.
Three-Step Method
- Isolate the radical on one side of the equation
- Square both sides to eliminate the radical (if √(expression) = c, then expression = c²)
- CHECK every solution by substituting back into the ORIGINAL equation
Example: Solve √(2x − 3) = 5
- Right side c = 5 ≥ 0 ✓ (solution may exist)
- Square both sides: 2x − 3 = 25
- Solve: 2x = 28 → x = 14
- CHECK (CRITICAL): √(2(14) − 3) = √(28 − 3) = √25 = 5 = right side ✓
- Solution: x = 14
Extraneous solution warning: When you square both sides of a radical equation, you may introduce solutions that satisfy the squared equation but NOT the original equation. These are called extraneous solutions and must be rejected. ALWAYS substitute every candidate solution back into the ORIGINAL equation to check.
Example with Extraneous Solution: √(x + 4) = x − 2
- Square both sides: x + 4 = (x−2)² = x² − 4x + 4
- Rearrange: 0 = x² − 5x → x(x−5) = 0
- Solutions: x = 0 or x = 5
- CHECK x = 0: √(0+4) = √4 = 2, but 0−2 = −2. Since 2 ≠ −2, x = 0 is EXTRANEOUS ✗
- CHECK x = 5: √(5+4) = √9 = 3, and 5−2 = 3. Since 3 = 3 ✓, x = 5 is valid.
- Solution: x = 5 only — reject x = 0 (extraneous solution)
Common Mistakes With Radical Simplification
Mistake 1 — Adding Unlike Radicals: √2 + √3 ≠ √5
- ❌ Wrong: √2 + √3 = √5
- ✅ Correct: √2 + √3 cannot be combined — different radicands make them unlike radicals
- Remember: √(a+b) ≠ √a + √b — this rule ONLY works for multiplication/division, not addition
Mistake 2 — Incomplete Simplification
- ❌ Wrong: √72 = 2√18 (pulled out 4, not 36)
- ✅ Correct: √72 = 6√2 (must use the LARGEST perfect square factor, which is 36)
- Check: does √18 have a perfect square factor? Yes — 18 = 9×2, so 2√18 = 2×3√2 = 6√2
Mistake 3 — Skipping the Check in Radical Equations
- ❌ Wrong: Accepting all solutions from the squared equation without checking
- ✅ Correct: Always substitute every candidate solution into the ORIGINAL radical equation
- Extraneous solutions arise because (−5)² = 25 = 5², so squaring masks sign information
Mistake 4 — Product Rule Applied to Addition: √(a+b) ≠ √a + √b
- ❌ Wrong: √(4+9) = √4 + √9 = 2 + 3 = 5
- ✅ Correct: √(4+9) = √13 ≈ 3.606 (not 5)
- The product rule √a × √b = √(ab) works ONLY for multiplication, never addition
Mistake 5 — Forgetting |x| When Simplifying √(x²)
- ❌ Wrong: √(x²) = x (fails when x is negative)
- ✅ Correct: √(x²) = |x| in general; √(x²) = x ONLY when x ≥ 0
- Example: if x = −3, then x² = 9, √9 = 3 = |−3|, NOT −3
Worked Examples — 10 Complete Problems
1. Simplify √108
- 108 = 36 × 3 (36 is the largest perfect square factor)
- √108 = √36 × √3 = 6√3
- Prime check: 108 = 2²×3³ → √108 = 2×3√3 = 6√3 ✓
- Answer: 6√3 · Decimal: √108 ≈ 10.392 = 6×1.732 ✓
2. Simplify √(50x⁴y³)
- √50 = 5√2 (50 = 25×2)
- √(x⁴) = x² (even power, perfect square)
- √(y³) = y√y (y³ = y²×y)
- Outside: 5×x²×y = 5x²y · Inside: √(2y)
- Answer: 5x²y√(2y)
3. Add: 2√12 + 3√27
- 2√12 = 2×2√3 = 4√3
- 3√27 = 3×3√3 = 9√3
- Like radicals (radicand 3): 4√3 + 9√3 = 13√3
- Answer: 13√3
4. Subtract: √50 − 2√8
- √50 = 5√2, 2√8 = 2×2√2 = 4√2
- 5√2 − 4√2 = √2
- Answer: √2
5. Add Unlike: √8 + √18 + √3
- √8 = 2√2, √18 = 3√2, √3 = √3
- Like groups: 2√2 + 3√2 = 5√2 and √3 (unlike — different radicand)
- Answer: 5√2 + √3
6. Multiply: 4√6 × 3√10
- Coefficients: 4×3=12; Radicands: √6×√10=√60 (product rule √a×√b=√(ab))
- Simplify √60: 60=4×15, √60=2√15
- 12×2√15 = 24√15
7. FOIL: (2 + √3)(5 − √3)
- F: 2×5=10 · O: 2×(−√3)=−2√3 · I: √3×5=5√3 · L: √3×(−√3)=−3
- Combine: (10−3) + (−2√3+5√3) = 7+3√3
- Answer: 7 + 3√3
8. Rationalize: 6/√12
- Multiply by √12/√12: 6√12/12 = √12/2
- Simplify √12 = 2√3: (2√3)/2 = √3
- Answer: √3
9. Rationalize Denominator: 3/(2 + √7)
- Conjugate of (2+√7) is (2−√7)
- Numerator: 3(2−√7) = 6−3√7
- Denominator: 4−7=−3
- (6−3√7)/(−3) = −2+√7
- Answer: √7 − 2
10. Solve: √(3x + 1) = 4, check for extraneous solutions
- c=4≥0 ✓
- Square: 3x+1=16 → 3x=15 → x=5
- CHECK: √(3(5)+1)=√16=4=right side ✓
- Solution: x=5 (valid, no extraneous solution)
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