Partial Pressure Calculator
This partial pressure calculator finds partial pressure using Dalton's Law, mole fractions, and the ideal gas law. Learn how to find partial pressure for gas mixtures with multiple components — results shown instantly in atm, kPa, mmHg, bar, and all common pressure units.
Enter the name and partial pressure of each gas. All pressures are converted to the same unit before summing.
| Gas | Partial P (atm) | Mole Fraction χ | % of Total |
|---|
Enter moles of each gas. The calculator computes mole fractions and partial pressures automatically. PA = χA × Ptotal
| Gas | Moles | χ (decimal) | χ (%) | P (atm) | P (kPa) | P (mmHg) |
|---|
Enter each gas component. Common gas molar masses are auto-filled when you type the gas name (e.g. "O2", "N2", "CO2"). PA = χA × Ptotal
| Gas | Moles | χ | χ% | P (atm) | P (kPa) | P (mmHg) | P (bar) |
|---|
What is Partial Pressure? — Dalton's Law of Partial Pressures
Partial pressure is the pressure that a single gas in a mixture would exert if it alone occupied the entire volume of the container at the same temperature. It represents that individual gas's contribution to the total pressure of the mixture. John Dalton formulated his Law of Partial Pressures in 1801: the total pressure of a gas mixture is the sum of the partial pressures of all component gases.
This law assumes ideal gas behaviour — gas molecules do not interact with one another and occupy negligible volume themselves. In practice it is highly accurate for most gases under ordinary conditions.
Real-World Example: Atmospheric Air at Sea Level
- N2 contributes ~78% → PN2 ≈ 0.7808 atm
- O2 contributes ~21% → PO2 ≈ 0.2095 atm
- Ar contributes ~1% → PAr ≈ 0.00934 atm
- Ptotal = 0.7808 + 0.2095 + 0.00934 ≈ 1.000 atm ✓
Applications of Dalton's Law
- Scuba diving: partial pressure of O2 and N2 increase with depth; narcosis and oxygen toxicity depend on their partial pressures.
- Respiratory physiology: partial pressure of O2 in alveoli drives gas exchange across the lung membrane.
- Industrial gas: storage and handling of gas mixtures require calculating individual partial pressures for safety limits.
- Anesthesiology: anesthetic gases exert their effect proportional to their partial pressure in the blood.
Partial Pressure Formula — Mole Fraction Method
The mole fraction method is the most common way to calculate partial pressure in chemistry. It directly connects the amount of each gas to the pressure it exerts. PA = χA × Ptotal
Key properties of mole fraction: it is dimensionless (no units), always between 0 and 1, and the sum of all mole fractions in a mixture exactly equals 1: Σχi = 1. For ideal gases at the same T and P, mole fraction equals volume fraction and pressure fraction. Mole% = χ × 100%.
Example — Dry air: N2 mole fraction = 0.7809 = 78.09 mol%. At 1 atm: PN2 = χN2 × Ptotal = 0.7809 × 1 atm = 0.7809 atm = 79.12 kPa.
How to Find Partial Pressure — Step by Step
There are three main methods for how to find partial pressure. The correct method depends on what information you are given.
Method 1: From Known Partial Pressures (Dalton's Law) — Ptotal = P1 + P2 + P3
- List all partial pressures in the same units.
- Add them: Ptotal = P1 + P2 + … + Pn.
- Unknown partial pressure = Ptotal − (sum of all known partial pressures).
Method 2: From Moles and Total Pressure
- Find moles of each gas.
- ntotal = Σni.
- χA = nA / ntotal.
- PA = χA × Ptotal.
Method 3: From Ideal Gas Law
- Note nA (mol), V (L), T (K).
- PA = nA × R × T / V.
- Use R = 0.082057 L·atm/(mol·K).
Worked Example — Air Composition: 3.12 mol N2, 0.84 mol O2, 0.04 mol Ar, Ptotal = 4.00 atm
- ntotal = 3.12 + 0.84 + 0.04 = 4.00 mol
- χN2 = 3.12 / 4.00 = 0.780 → PN2 = 0.780 × 4.00 = 3.120 atm
- χO2 = 0.84 / 4.00 = 0.210 → PO2 = 0.210 × 4.00 = 0.840 atm
- χAr = 0.04 / 4.00 = 0.010 → PAr = 0.010 × 4.00 = 0.040 atm
- Check: 3.120 + 0.840 + 0.040 = 4.000 atm ✓ | χ sum: 0.780 + 0.210 + 0.010 = 1.000 ✓
How to Calculate Partial Pressure from Moles
When you know the mass or moles of each gas and the total pressure, use this four-step method to calculate partial pressure from moles. This is the most common exam scenario.
- Step 1: Convert grams to moles if needed: n = mass(g) ÷ molar mass(g/mol)
- Step 2: Sum all moles: ntotal = Σni
- Step 3: Calculate mole fraction: χA = nA / ntotal
- Step 4: Partial pressure: PA = χA × Ptotal
Example 1: 14 g N2 and 16 g O2, Ptotal = 2.00 atm
- nN2 = 14 ÷ 28.014 = 0.4998 mol
- nO2 = 16 ÷ 31.998 = 0.5000 mol
- ntotal = 0.4998 + 0.5000 = 0.9998 mol
- χN2 = 0.4998 / 0.9998 = 0.4999 → PN2 = 0.4999 × 2.00 = 1.000 atm
- χO2 = 0.5000 / 0.9998 = 0.5001 → PO2 = 0.5001 × 2.00 = 1.000 atm
Example 2: 0.5 mol H2, 0.3 mol He, 0.2 mol Ar, Ptotal = 5.00 atm
- ntotal = 0.5 + 0.3 + 0.2 = 1.00 mol
- χH2 = 0.50 → PH2 = 0.50 × 5.00 = 2.50 atm
- χHe = 0.30 → PHe = 0.30 × 5.00 = 1.50 atm
- χAr = 0.20 → PAr = 0.20 × 5.00 = 1.00 atm
Example 3: Partial Pressure of Nitrogen in Dry Air at Sea Level
- Dry air: 78.09% N2 by mole → χN2 = 0.7809
- Ptotal = 101.325 kPa (1 atm)
- PN2 = χN2 × Ptotal = 0.7809 × 101.325 = 79.12 kPa = 0.7809 atm
Pressure Unit Conversion Table
Standard atmospheric pressure: 1 atm = 101.325 kPa = 760 mmHg = 1.01325 bar = 14.696 psi = 101,325 Pa
| Unit | = atm | = kPa | = mmHg | = bar | = Pa | = psi |
|---|---|---|---|---|---|---|
| 1 atm | 1 | 101.325 | 760 | 1.01325 | 101,325 | 14.696 |
| 1 kPa | 0.009869 | 1 | 7.5006 | 0.01 | 1,000 | 0.14504 |
| 1 mmHg (torr) | 0.001316 | 0.13332 | 1 | 0.001333 | 133.32 | 0.01934 |
| 1 bar | 0.98692 | 100 | 750.06 | 1 | 100,000 | 14.504 |
| 1 Pa | 9.869×10?6 | 0.001 | 0.0075 | 0.00001 | 1 | 0.000145 |
| 1 psi | 0.068046 | 6.8948 | 51.715 | 0.068948 | 6,894.8 | 1 |
Partial Pressure of Gases in Dry Air at Sea Level
At standard sea-level pressure (1 atm = 101.325 kPa = 760 mmHg), the partial pressures of the main atmospheric gases are:
| Gas | Mole Fraction (χ) | P (atm) | P (kPa) | P (mmHg) |
|---|---|---|---|---|
| Nitrogen (N2) | 0.78084 | 0.7808 atm | 79.12 kPa | 593.4 mmHg |
| Oxygen (O2) | 0.20946 | 0.2095 atm | 21.22 kPa | 159.2 mmHg |
| Argon (Ar) | 0.00934 | 0.00934 atm | 0.946 kPa | 7.10 mmHg |
| Carbon dioxide (CO2) | 0.000421 | 0.000421 atm | 0.0427 kPa | 0.320 mmHg |
| Total (dry air) | 1.00000 | 1.0000 atm | 101.325 kPa | 760.0 mmHg |
Note: partial pressure of oxygen in the alveoli of the lungs is lower (~13.3 kPa) due to dilution by water vapour (~6.3 kPa) and CO2 (~5.3 kPa) in the alveolar air. Partial pressure of nitrogen at sea level: PN2 = 0.7808 atm = 79.12 kPa = 593.4 mmHg.
Worked Examples
1. Finding Partial Pressure Using Dalton's Law (Ptotal = P1 + P2 + P3)
Three gases are in a container: PN2 = 0.78 atm, PO2 = 0.21 atm, PAr = 0.01 atm. By Dalton's Law, Ptotal = PN2 + PO2 + PAr = 0.78 + 0.21 + 0.01 = 1.00 atm. To find an unknown partial pressure, rearrange: Punknown = Ptotal − (sum of known pressures).
2. Partial Pressure from Mole Fraction — PA = χA × Ptotal
A gas mixture has Ptotal = 3.00 atm. Gas A has χA = 0.40. Apply the formula: PA = χA × Ptotal = 0.40 × 3.00 = 1.20 atm = 121.6 kPa. Verify: if χB = 0.60, then PB = 0.60 × 3.00 = 1.80 atm; 1.20 + 1.80 = 3.00 atm ✓.
3. Partial Pressure from Moles and Total Pressure
3 mol N2 and 1 mol O2 at Ptotal = 4 atm. ntotal = 4 mol. χN2 = 3/4 = 0.75 → PN2 = 0.75 × 4 = 3.00 atm. χO2 = 1/4 = 0.25 → PO2 = 0.25 × 4 = 1.00 atm. Check: 3.00 + 1.00 = 4.00 ✓.
4. Finding Total Pressure from Partial Pressures
Given PH2 = 250 mmHg, PHe = 375 mmHg, PAr = 135 mmHg. Convert to same unit (already in mmHg). Ptotal = P1 + P2 + P3 = 250 + 375 + 135 = 760 mmHg = 1.00 atm. Dalton's Law requires all pressures in the same unit before summing.
5. Partial Pressure Using the Ideal Gas Law — PA = nART/V
n = 0.5 mol O2, V = 10 L, T = 25°C = 298.15 K. PO2 = (0.5 × 0.082057 × 298.15) / 10 = 12.232 / 10 = 1.223 atm = 123.9 kPa. Always convert °C to K by adding 273.15 before using PV = nRT.
6. Partial Pressure of Oxygen in Air
Oxygen makes up 20.946% of dry air by mole. χO2 = 0.20946. At Ptotal = 1 atm: PO2 = χO2 × Ptotal = 0.20946 × 1 = 0.2095 atm = 21.22 kPa = 159.2 mmHg. In the lungs this drops to ~13.3 kPa due to water vapour and CO2.
7. Partial Pressure of Nitrogen at Sea Level
N2 mole fraction in dry air = 0.78084. At 1 atm: PN2 = 0.78084 × 1 atm = 0.7808 atm = 0.7808 × 101.325 = 79.12 kPa = 0.7808 × 760 = 593.4 mmHg. This is the partial pressure of nitrogen that causes nitrogen narcosis in scuba diving at depth.
8. Partial Pressure from Grams of Each Gas
32 g O2 and 28 g N2 in a container at Ptotal = 3 atm. nO2 = 32/31.998 = 1.000 mol; nN2 = 28/28.014 = 0.9995 mol; ntotal = 1.9995 mol. χO2 = 1.000/1.9995 = 0.5001; PO2 = 0.5001 × 3 = 1.500 atm. χN2 = 0.4999; PN2 = 0.4999 × 3 = 1.500 atm.
9. Mole Fraction from Partial Pressure
If Ptotal = 5.00 atm and PCO2 = 0.75 atm, find χCO2. Rearrange PA = χA × Ptotal: χCO2 = PCO2 / Ptotal = 0.75 / 5.00 = 0.150 = 15.0 mol%. This confirms that mole fraction = pressure fraction for ideal gases.
10. Partial Pressure in a Three-Component Gas Mixture
2 mol CH4, 1 mol CO2, 0.5 mol H2, Ptotal = 7.00 atm. ntotal = 3.5 mol. χCH4 = 2/3.5 = 0.5714 → PCH4 = 0.5714 × 7 = 4.000 atm. χCO2 = 1/3.5 = 0.2857 → PCO2 = 2.000 atm. χH2 = 0.5/3.5 = 0.1429 → PH2 = 1.000 atm. Sum: 4+2+1 = 7.00 ✓.
Frequently Asked Questions
Related Calculators
| 1 atm | = 101.325 kPa |
| 1 atm | = 760 mmHg |
| 1 atm | = 1.01325 bar |
| 1 atm | = 14.696 psi |
| 1 atm | = 101,325 Pa |
| N2 | 28.014 g/mol |
| O2 | 31.998 g/mol |
| CO2 | 44.009 g/mol |
| H2 | 2.016 g/mol |
| He | 4.003 g/mol |
| Ar | 39.948 g/mol |
| CH4 | 16.043 g/mol |
| NH3 | 17.031 g/mol |