Beam Calculator — Shear, Moment & Deflection
Free online beam calculator for shear force, bending moment, reaction forces, and deflection. Draws SFD and BMD diagrams for simply supported, cantilever, and fixed beams with full step-by-step working.
Enter deflection or moment results from up to 3 separate load cases. The superposition principle states the total response of a linear structure equals the sum of responses from each individual load.
Beam Analysis Report
Generated:
Complete Guide to Beam Analysis
This beam calculator solves shear force, bending moment, reaction forces, and deflection for any beam configuration. It automatically draws the shear and moment diagrams (SFD and BMD) with full step-by-step working for simply supported beams, cantilever beams, and fixed-fixed beams.
Beam Types Explained
Understanding the three main beam types is the foundation of structural beam analysis and beam design.
1. Simply Supported Beam
A simply supported beam rests on two supports: a pin (resists vertical and horizontal forces) and a roller (resists only vertical force). It cannot resist moments at the supports. Common uses: floor joists, bridges, lintels.
Key formula: For a central point load P, max moment M = PL/4 and max deflection δ = PL³/48EI.
2. Cantilever Beam
A cantilever beam is fixed at one end and free at the other. The fixed end resists vertical force, horizontal force, AND moment. Common uses: balconies, diving boards, aircraft wings, signposts.
Key formula: For a tip point load P, max moment M = PL at the wall, max deflection δ = PL³/3EI at the tip.
3. Fixed-Fixed Beam
A fixed-fixed beam (or built-in beam) is rigidly clamped at both ends. Both ends resist forces and moments. Stiffer than simply supported — same load produces ¼ the deflection. Common uses: built-in slabs, frame structures.
Key formula: For a central point load P, max moment M = PL/8 at the supports, max deflection δ = PL³/192EI at midspan.
How to Calculate Shear Force and Bending Moment
Here is the step-by-step method that every shear force and bending moment calculator uses internally, demonstrated with a worked example.
Worked Example: Simply Supported Beam, L = 6 m, P = 20 kN at center
- Draw the Free Body Diagram (FBD): Sketch the beam, mark the pin support A (left), roller support B (right), and the 20 kN point load at midspan (x = 3 m).
- Apply equilibrium ΣFy = 0: RA + RB − 20 = 0 → RA + RB = 20 kN.
- Apply ΣMA = 0: Take moments about A. RB(6) − 20(3) = 0 → RB = 10 kN. Therefore RA = 10 kN.
- Shear force equation (0 ≤ x < 3): V(x) = RA = +10 kN.
- Shear force equation (3 ≤ x ≤ 6): V(x) = RA − 20 = −10 kN.
- Bending moment equation (0 ≤ x ≤ 3): M(x) = RA·x = 10x kN·m.
- Max bending moment: At x = 3 m: Mmax = 10(3) = 30 kN·m. (Check: PL/4 = 20·6/4 = 30 ✓)
Sign convention: Shear is positive when the left side pushes up. Moment is positive when it bends the beam concave-up (sagging). Use this convention consistently throughout the entire beam.
Beam Deflection Formulas Reference Table
The most commonly used beam deflection and beam equations, organized by support condition and loading.
| Beam Type | Max Deflection (δmax) | Max Moment (Mmax) | Location |
|---|---|---|---|
| Simply supported, central point load P | PL³ / 48EI | PL / 4 | Midspan |
| Simply supported, UDL w | 5wL⁴ / 384EI | wL² / 8 | Midspan |
| Cantilever, tip point load P | PL³ / 3EI | PL | Tip / Wall |
| Cantilever, UDL w | wL⁴ / 8EI | wL² / 2 | Tip / Wall |
| Fixed-fixed, central point load P | PL³ / 192EI | PL / 8 | Midspan / Supports |
| Fixed-fixed, UDL w | wL⁴ / 384EI | wL² / 12 | Midspan / Supports |
Worked Examples — All Beam Calculations
1. How to Calculate Reaction Forces for a Simply Supported Beam
For any simply supported beam, use two equilibrium equations: ΣFy = 0 (vertical forces balance) and ΣM = 0 about one support (moments balance about that point). Take moments about the support whose reaction you don't yet know — that reaction has zero moment arm and drops out.
Example: Beam L = 8 m, point load 40 kN at x = 3 m from A. ΣMA = 0: RB(8) − 40(3) = 0 → RB = 15 kN. Then RA = 40 − 15 = 25 kN.
2. How to Draw a Shear Force Diagram Step by Step
Start from the left end at V = 0. Move right along the beam — at every point load or reaction, the shear jumps vertically by that force amount (up for upward forces, down for downward). Between point loads with no UDL, shear is constant (horizontal line). Under a UDL, shear varies linearly with slope = −w.
Example: L = 6 m, RA = 10 kN, 20 kN load at x = 3 m, RB = 10 kN. SFD: jumps up to +10 at A, stays +10 until x = 3, jumps down to −10, stays −10 until x = 6, jumps up to 0 at B. Vmax = 10 kN.
3. How to Draw a Bending Moment Diagram Step by Step
Moment at any point = area under the shear diagram up to that point. Start at M = 0 at a pin or roller support. For point loads, the BMD is triangular (linear segments). For UDL, the BMD is parabolic (curve). Maximum moment occurs where shear crosses zero.
Example: Same beam as above. At x = 0, M = 0. At x = 3 m, M = +10 × 3 = +30 kN·m (area of rectangle). At x = 6 m, M = 30 + (−10 × 3) = 0. Mmax = 30 kN·m at midspan.
4. How to Calculate Maximum Deflection of a Cantilever Beam
For a cantilever with point load P at the tip: δmax = PL³ / (3EI). For UDL w: δmax = wL⁴ / (8EI). Make sure units are consistent — convert E to N/m², I to m⁴, and L to m.
Example: Cantilever L = 3 m, P = 10 kN at tip, E = 200 GPa = 200×10⁹ N/m², I = 1000 cm⁴ = 1000×10⁻⁸ m⁴ = 1×10⁻⁵ m⁴. δ = (10000 × 27) / (3 × 200×10⁹ × 1×10⁻⁵) = 270000 / 6×10⁶ = 0.045 m = 45 mm.
5. How to Calculate Bending Stress in a Beam
Bending stress σ = M·c / I, where M is bending moment at the section, c is the distance from the neutral axis to the outermost fiber (half the section depth for symmetric sections), and I is the moment of inertia about the neutral axis. Use consistent SI units (Pa).
Example: M = 30 kN·m = 30,000 N·m, c = 100 mm = 0.1 m, I = 1000 cm⁴ = 1×10⁻⁵ m⁴. σ = 30000 × 0.1 / 1×10⁻⁵ = 300 MPa.
6. How to Find the Moment Diagram for a Cantilever Beam
For a cantilever with tip load P, the moment is maximum at the fixed wall and zero at the free end. M(x) = −P(L − x), measured from the wall. The diagram is a triangle peaking at the wall with magnitude PL.
Example: L = 4 m, P = 5 kN at tip. Mmax at wall = −5 × 4 = −20 kN·m (negative because the beam curves downward — hogging).
7. What is the Superposition Method for Beams?
The superposition principle states that for a linear elastic structure, the total response (deflection, moment, shear, stress) under combined loads equals the algebraic sum of responses from each load applied separately. This works because beam equations are linear in load.
Example: A simply supported beam carries a central point load AND a UDL. Calculate δ from each load separately using table formulas, then add: δtotal = PL³/48EI + 5wL⁴/384EI.
8. How to Calculate Beam Size for a Given Load
Find the required moment of inertia I from the allowable deflection limit (e.g., L/360), then choose a section from steel tables that has at least that I. Also check bending stress σ = Mc/I ≤ σallow.
Example: Simply supported L = 5 m with UDL 10 kN/m, allow δ = L/360 = 13.9 mm. Rearrange: Ireq = 5wL⁴ / (384·E·δ) = 5(10000)(5⁴) / (384 × 200×10⁹ × 0.0139) ≈ 2.93×10⁻⁵ m⁴ = 2930 cm⁴.
9. How to Use the Moment Calculator
The moment calculator computes M = F × d, where F is the force and d is the perpendicular distance (moment arm) from the pivot. To reverse, F = M / d. Make sure F is perpendicular to d — otherwise use F·d·sin(θ).
Example: F = 100 kN, d = 2 m → M = 200 kN·m. Reverse: M = 500 N·m, d = 0.25 m → F = 500/0.25 = 2000 N.
10. How to Find Shear Force at Any Point on a Beam
Cut the beam at the point of interest and sum all vertical forces on one side: V = ΣFy (left of cut). Upward forces are positive. This gives the shear at that location.
Example: Same beam (RA = 10 kN, load 20 kN at midspan). At x = 1.5 m (left of load): V = +10 kN. At x = 4.5 m (right of load): V = 10 − 20 = −10 kN.
Beam Load Quick Reference Table
This beam load calculator reference table shows approximate max moment and deflection for simply supported steel beams (E = 200 GPa, I = 1000 cm⁴) under uniform distributed loads.
| Span L (m) | UDL w (kN/m) | Mmax = wL²/8 (kN·m) | δmax (mm) |
|---|---|---|---|
| 3 | 5 | 5.6 | 2.6 |
| 3 | 10 | 11.3 | 5.3 |
| 3 | 20 | 22.5 | 10.5 |
| 5 | 5 | 15.6 | 20.3 |
| 5 | 10 | 31.3 | 40.7 |
| 5 | 20 | 62.5 | 81.4 |
| 6 | 10 | 45.0 | 84.4 |
| 8 | 10 | 80.0 | 266.7 |
| 10 | 5 | 62.5 | 325.5 |
| 10 | 10 | 125.0 | 651.0 |
FAQs
| Material | E (GPa) |
|---|---|
| Steel | 200 |
| Aluminum | 69 |
| Concrete | 30 |
| Timber (pine) | 10 |
| Cast Iron | 100 |
| Brass | 110 |
| Titanium | 110 |
| Glass | 70 |
Share This Tool
Share the Beam Calculator with engineers and students!